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Class 10 NCERT Solutions Maths Chapter 8 - Introduction to Trigonometry

Introduction to Trigonometry Exercise Ex. 8.1

Solution 1

In ABC by applying Pythagoras theorem
AC2 = AB2 + BC2
      = (24)2 + (7)2
      = 576 + 49
      = 625
AC =  = 25 cm





cos space straight C space equals space fraction numerator Side space adjacent space to space angle straight C over denominator hypotenuse end fraction space equals space BC over AC equals space 7 over 25

Solution 2

Solution 3

Solution 4

Solution 5

Solution 6

 

Since angleA and angleB are acute angles, then angleC is a right angle.

cos A = cos B .... given

AC/AB = BC/AB

AC = BC

angleB =angleA           .... angles opposite to equal sides are equal in length.





Solution 7

Solution 8

Solution 9

Solution 10

Solution 11

Introduction to Trigonometry Exercise Ex. 8.2

Solution 1

Solution 2


Solution 3

Solution 4

Introduction to Trigonometry Exercise Ex. 8.3

Solution 1

We know that

Solution 2

We know that

Solution 3

(i) 9sec2A - 9tan2A
= 9(sec2A - tan2A)
= 9 (1)            (as sec2A - tan2A = 1)
= 9
Hence alternative (B) is correct.

(ii) (1 + tanθ + secθ) (1 + cotθ - cosecθ)

Hence alternative (C) is correct.


(iii) (secA + tanA) (1 - sinA)


(iv)

Solution 4







 


 

 

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